Question
Answer
$$(7w+b-10)^2=b^2+14bw+49w^2-20b-140w+100$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7w+b-10)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}b^2+14bw+49w^2-20b-140w+100\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7w+b-10}\right) $ by each term in $ \left( 7w+b-10\right) $. $$ \left( \color{blue}{7w+b-10}\right) \cdot \left( 7w+b-10\right) = 49w^2+7bw-70w+7bw+b^2-10b-70w-10b+100 $$ |
| ② | Combine like terms: $$ 49w^2+ \color{blue}{7bw} \color{red}{-70w} + \color{blue}{7bw} +b^2 \color{green}{-10b} \color{red}{-70w} \color{green}{-10b} +100 = \\ = b^2+ \color{blue}{14bw} +49w^2 \color{green}{-20b} \color{red}{-140w} +100 $$ |
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