Question
Answer
$$(7b^5-b^2)^2=49b^{10}-14b^7+b^4$$
Explanation
| $$ \begin{aligned}(7b^5-b^2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}49b^{10}-14b^7+b^4\end{aligned} $$ | |
| ① | Find $ \left(7b^5-b^2\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 7b^5 } $ and $ B = \color{red}{ b^2 }$. $$ \begin{aligned}\left(7b^5-b^2\right)^2 = \color{blue}{\left( 7b^5 \right)^2} -2 \cdot 7b^5 \cdot b^2 + \color{red}{\left( b^2 \right)^2} = 49b^{10}-14b^7+b^4\end{aligned} $$ |
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