Question
Answer
$$(7-8y)(2y+6)=-16y^2-34y+42$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(7-8y)(2y+6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}14y+42-16y^2-48y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-16y^2-34y+42\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{7-8y}\right) $ by each term in $ \left( 2y+6\right) $. $$ \left( \color{blue}{7-8y}\right) \cdot \left( 2y+6\right) = 14y+42-16y^2-48y $$ |
| ② | Combine like terms: $$ \color{blue}{14y} +42-16y^2 \color{blue}{-48y} = -16y^2 \color{blue}{-34y} +42 $$ |
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