Question
Answer
$$(6y-10x)^2=100x^2-120xy+36y^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6y-10x)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}36y^2-120xy+100x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}100x^2-120xy+36y^2\end{aligned} $$ | |
| ① | Find $ \left(6y-10x\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 6y } $ and $ B = \color{red}{ 10x }$. $$ \begin{aligned}\left(6y-10x\right)^2 = \color{blue}{\left( 6y \right)^2} -2 \cdot 6y \cdot 10x + \color{red}{\left( 10x \right)^2} = 36y^2-120xy+100x^2\end{aligned} $$ |
| ② | Combine like terms: $$ 100x^2-120xy+36y^2 = 100x^2-120xy+36y^2 $$ |
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