Question
Answer
$$(6x-5)(2x+3)=12x^2+8x-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6x-5)(2x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^2+18x-10x-15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2+8x-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6x-5}\right) $ by each term in $ \left( 2x+3\right) $. $$ \left( \color{blue}{6x-5}\right) \cdot \left( 2x+3\right) = 12x^2+18x-10x-15 $$ |
| ② | Combine like terms: $$ 12x^2+ \color{blue}{18x} \color{blue}{-10x} -15 = 12x^2+ \color{blue}{8x} -15 $$ |
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