Question
Answer
$$6x^3-4+3(4x^2-2x^3)=12x^2-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6x^3-4+3(4x^2-2x^3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^3-4+12x^2-6x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2-4\end{aligned} $$ | |
| ① | Multiply $ \color{blue}{3} $ by $ \left( 4x^2-2x^3\right) $ $$ \color{blue}{3} \cdot \left( 4x^2-2x^3\right) = 12x^2-6x^3 $$ |
| ② | Combine like terms: $$ \, \color{blue}{ \cancel{6x^3}} \,-4+12x^2 \, \color{blue}{ -\cancel{6x^3}} \, = 12x^2-4 $$ |
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