Question
Answer
$$6x^2+3x-2-(2x^2-2x+3)=4x^2+5x-5$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6x^2+3x-2-(2x^2-2x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2+3x-2-2x^2+2x-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2+5x-5\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2x^2-2x+3 \right) = -2x^2+2x-3 $$ |
| ② | Combine like terms: $$ \color{blue}{6x^2} + \color{red}{3x} \color{green}{-2} \color{blue}{-2x^2} + \color{red}{2x} \color{green}{-3} = \color{blue}{4x^2} + \color{red}{5x} \color{green}{-5} $$ |
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