Question
Answer
$$(6x^2+3x)(-6x-3)=-36x^3-36x^2-9x$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6x^2+3x)(-6x-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-36x^3-18x^2-18x^2-9x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-36x^3-36x^2-9x\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6x^2+3x}\right) $ by each term in $ \left( -6x-3\right) $. $$ \left( \color{blue}{6x^2+3x}\right) \cdot \left( -6x-3\right) = -36x^3-18x^2-18x^2-9x $$ |
| ② | Combine like terms: $$ -36x^3 \color{blue}{-18x^2} \color{blue}{-18x^2} -9x = -36x^3 \color{blue}{-36x^2} -9x $$ |
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