Question
Answer
$$(6f-7)(8f-9)=48f^2-110f+63$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6f-7)(8f-9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}48f^2-54f-56f+63 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}48f^2-110f+63\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6f-7}\right) $ by each term in $ \left( 8f-9\right) $. $$ \left( \color{blue}{6f-7}\right) \cdot \left( 8f-9\right) = 48f^2-54f-56f+63 $$ |
| ② | Combine like terms: $$ 48f^2 \color{blue}{-54f} \color{blue}{-56f} +63 = 48f^2 \color{blue}{-110f} +63 $$ |
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