Question
Answer
$$(6a-5)(7a+3)=42a^2-17a-15$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6a-5)(7a+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}42a^2+18a-35a-15 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}42a^2-17a-15\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6a-5}\right) $ by each term in $ \left( 7a+3\right) $. $$ \left( \color{blue}{6a-5}\right) \cdot \left( 7a+3\right) = 42a^2+18a-35a-15 $$ |
| ② | Combine like terms: $$ 42a^2+ \color{blue}{18a} \color{blue}{-35a} -15 = 42a^2 \color{blue}{-17a} -15 $$ |
This page was created using
Simplify polynomials calculator