$$ x x x = x^{1 + 1 + 1} = x^3 $$

Find $ \left(34x+2\right)^2 $ using formula.

$$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$

where $ A = \color{blue}{ 34x } $ and $ B = \color{red}{ 2 }$.

$$ \begin{aligned}\left(34x+2\right)^2 = \color{blue}{\left( 34x \right)^2} +2 \cdot 34x \cdot 2 + \color{red}{2^2} = 1156x^2+136x+4\end{aligned} $$

Multiply each term of $ \left( \color{blue}{65-x}\right) $ by each term in $ \left( 1156x^2+136x+4\right) $.

$$ \left( \color{blue}{65-x}\right) \cdot \left( 1156x^2+136x+4\right) = 75140x^2+8840x+260-1156x^3-136x^2-4x $$Multiply $ \color{blue}{28} $ by $ \left( x-1\right) $ $$ \color{blue}{28} \cdot \left( x-1\right) = 28x-28 $$

Combine like terms:

$$ \color{blue}{75140x^2} + \color{red}{8840x} +260-1156x^3 \color{blue}{-136x^2} \color{red}{-4x} = -1156x^3+ \color{blue}{75004x^2} + \color{red}{8836x} +260 $$

Multiply each term of $ \left( \color{blue}{28x-28}\right) $ by each term in $ \left( x^3+3\right) $.

$$ \left( \color{blue}{28x-28}\right) \cdot \left( x^3+3\right) = 28x^4+84x-28x^3-84 $$

Remove the parentheses by changing the sign of each term within them.

$$ - \left( 28x^4+84x-28x^3-84 \right) = -28x^4-84x+28x^3+84 $$

Combine like terms:

$$ \color{blue}{-1156x^3} +75004x^2+ \color{red}{8836x} + \color{green}{260} -28x^4 \color{red}{-84x} + \color{blue}{28x^3} + \color{green}{84} = \\ = -28x^4 \color{blue}{-1128x^3} +75004x^2+ \color{red}{8752x} + \color{green}{344} $$