Question
Answer
$$6-2x+7x^2-(10x-3+3x^2)=4x^2-12x+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}6-2x+7x^2-(10x-3+3x^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6-2x+7x^2-10x+3-3x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-12x+9\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 10x-3+3x^2 \right) = -10x+3-3x^2 $$ |
| ② | Combine like terms: $$ \color{blue}{6} \color{red}{-2x} + \color{green}{7x^2} \color{red}{-10x} + \color{blue}{3} \color{green}{-3x^2} = \color{green}{4x^2} \color{red}{-12x} + \color{blue}{9} $$ |
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