Question
Answer
$$(6-2x)\cdot(10-2x)=4x^2-32x+60$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(6-2x)\cdot(10-2x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}60-12x-20x+4x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-32x+60\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{6-2x}\right) $ by each term in $ \left( 10-2x\right) $. $$ \left( \color{blue}{6-2x}\right) \cdot \left( 10-2x\right) = 60-12x-20x+4x^2 $$ |
| ② | Combine like terms: $$ 60 \color{blue}{-12x} \color{blue}{-20x} +4x^2 = 4x^2 \color{blue}{-32x} +60 $$ |
This page was created using
Simplify polynomials calculator