| $$ \begin{aligned}(5x+4)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}25x^2+40x+16\end{aligned} $$ | |
| ① | Find $ \left(5x+4\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 5x } $ and $ B = \color{red}{ 4 }$. $$ \begin{aligned}\left(5x+4\right)^2 = \color{blue}{\left( 5x \right)^2} +2 \cdot 5x \cdot 4 + \color{red}{4^2} = 25x^2+40x+16\end{aligned} $$ |