Question
Answer
$$(5x-4)(8x-11)=40x^2-87x+44$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5x-4)(8x-11)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}40x^2-55x-32x+44 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}40x^2-87x+44\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5x-4}\right) $ by each term in $ \left( 8x-11\right) $. $$ \left( \color{blue}{5x-4}\right) \cdot \left( 8x-11\right) = 40x^2-55x-32x+44 $$ |
| ② | Combine like terms: $$ 40x^2 \color{blue}{-55x} \color{blue}{-32x} +44 = 40x^2 \color{blue}{-87x} +44 $$ |
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