Question
Answer
$$(5x^3-2x)(x^4+3x^2)=5x^7+13x^5-6x^3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5x^3-2x)(x^4+3x^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5x^7+15x^5-2x^5-6x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}5x^7+13x^5-6x^3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5x^3-2x}\right) $ by each term in $ \left( x^4+3x^2\right) $. $$ \left( \color{blue}{5x^3-2x}\right) \cdot \left( x^4+3x^2\right) = 5x^7+15x^5-2x^5-6x^3 $$ |
| ② | Combine like terms: $$ 5x^7+ \color{blue}{15x^5} \color{blue}{-2x^5} -6x^3 = 5x^7+ \color{blue}{13x^5} -6x^3 $$ |
This page was created using
Simplify polynomials calculator