Question
Answer
$$5x^2+8y^2-3-(7x^2+8y^2-5)=-2x^2+2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}5x^2+8y^2-3-(7x^2+8y^2-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}5x^2+8y^2-3-7x^2-8y^2+5 \xlongequal{ } \\[1 em] & \xlongequal{ }5x^2+ \cancel{8y^2}-3-7x^2 -\cancel{8y^2}+5 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-2x^2+2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 7x^2+8y^2-5 \right) = -7x^2-8y^2+5 $$ |
| ② | Combine like terms: $$ \color{blue}{5x^2} + \, \color{red}{ \cancel{8y^2}} \, \color{orange}{-3} \color{blue}{-7x^2} \, \color{red}{ -\cancel{8y^2}} \,+ \color{orange}{5} = \color{blue}{-2x^2} + \color{orange}{2} $$ |
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