Question
Answer
$$(5v-1)(4v+3)=20v^2+11v-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5v-1)(4v+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20v^2+15v-4v-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20v^2+11v-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5v-1}\right) $ by each term in $ \left( 4v+3\right) $. $$ \left( \color{blue}{5v-1}\right) \cdot \left( 4v+3\right) = 20v^2+15v-4v-3 $$ |
| ② | Combine like terms: $$ 20v^2+ \color{blue}{15v} \color{blue}{-4v} -3 = 20v^2+ \color{blue}{11v} -3 $$ |
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