Question
Answer
$$(5a-4)(8a+1)=40a^2-27a-4$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(5a-4)(8a+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}40a^2+5a-32a-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}40a^2-27a-4\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{5a-4}\right) $ by each term in $ \left( 8a+1\right) $. $$ \left( \color{blue}{5a-4}\right) \cdot \left( 8a+1\right) = 40a^2+5a-32a-4 $$ |
| ② | Combine like terms: $$ 40a^2+ \color{blue}{5a} \color{blue}{-32a} -4 = 40a^2 \color{blue}{-27a} -4 $$ |
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