Question
Answer
$$4y^2+6y-5-(-8y+4)=4y^2+14y-9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4y^2+6y-5-(-8y+4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4y^2+6y-5+8y-4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4y^2+14y-9\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( -8y+4 \right) = 8y-4 $$ |
| ② | Combine like terms: $$ 4y^2+ \color{blue}{6y} \color{red}{-5} + \color{blue}{8y} \color{red}{-4} = 4y^2+ \color{blue}{14y} \color{red}{-9} $$ |
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