Question
Answer
$$4y^2+2-(-8y^2+2y-4)=12y^2-2y+6$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4y^2+2-(-8y^2+2y-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4y^2+2+8y^2-2y+4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12y^2-2y+6\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( -8y^2+2y-4 \right) = 8y^2-2y+4 $$ |
| ② | Combine like terms: $$ \color{blue}{4y^2} + \color{red}{2} + \color{blue}{8y^2} -2y+ \color{red}{4} = \color{blue}{12y^2} -2y+ \color{red}{6} $$ |
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