Question
Answer
$$(4x+3-2x^2)^2=4x^4-16x^3+4x^2+24x+9$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x+3-2x^2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^4-16x^3+4x^2+24x+9\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x+3-2x^2}\right) $ by each term in $ \left( 4x+3-2x^2\right) $. $$ \left( \color{blue}{4x+3-2x^2}\right) \cdot \left( 4x+3-2x^2\right) = 16x^2+12x-8x^3+12x+9-6x^2-8x^3-6x^2+4x^4 $$ |
| ② | Combine like terms: $$ \color{blue}{16x^2} + \color{red}{12x} \color{green}{-8x^3} + \color{red}{12x} +9 \color{orange}{-6x^2} \color{green}{-8x^3} \color{orange}{-6x^2} +4x^4 = \\ = 4x^4 \color{green}{-16x^3} + \color{orange}{4x^2} + \color{red}{24x} +9 $$ |
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