Question
Answer
$$(4x-9)(x-5)=4x^2-29x+45$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-9)(x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^2-20x-9x+45 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^2-29x+45\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-9}\right) $ by each term in $ \left( x-5\right) $. $$ \left( \color{blue}{4x-9}\right) \cdot \left( x-5\right) = 4x^2-20x-9x+45 $$ |
| ② | Combine like terms: $$ 4x^2 \color{blue}{-20x} \color{blue}{-9x} +45 = 4x^2 \color{blue}{-29x} +45 $$ |
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