Question
Answer
$$(4x-8)(7x+11)=28x^2-12x-88$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-8)(7x+11)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}28x^2+44x-56x-88 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}28x^2-12x-88\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-8}\right) $ by each term in $ \left( 7x+11\right) $. $$ \left( \color{blue}{4x-8}\right) \cdot \left( 7x+11\right) = 28x^2+44x-56x-88 $$ |
| ② | Combine like terms: $$ 28x^2+ \color{blue}{44x} \color{blue}{-56x} -88 = 28x^2 \color{blue}{-12x} -88 $$ |
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