Question
Answer
$$(4x-3)^3=64x^3-144x^2+108x-27$$
Explanation
| $$ \begin{aligned}(4x-3)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}64x^3-144x^2+108x-27\end{aligned} $$ | |
| ① | Find $ \left(4x-3\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = 4x $ and $ B = 3 $. $$ \left(4x-3\right)^3 = \left( 4x \right)^3-3 \cdot \left( 4x \right)^2 \cdot 3 + 3 \cdot 4x \cdot 3^2-3^3 = 64x^3-144x^2+108x-27 $$ |
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