Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-1)(3x+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^2+8x-3x-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2+5x-2\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-1}\right) $ by each term in $ \left( 3x+2\right) $. $$ \left( \color{blue}{4x-1}\right) \cdot \left( 3x+2\right) = 12x^2+8x-3x-2 $$ |
| ② | Combine like terms: $$ 12x^2+ \color{blue}{8x} \color{blue}{-3x} -2 = 12x^2+ \color{blue}{5x} -2 $$ |