Question
Answer
$$(4x-1)(2x+3)=8x^2+10x-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x-1)(2x+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}8x^2+12x-2x-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8x^2+10x-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x-1}\right) $ by each term in $ \left( 2x+3\right) $. $$ \left( \color{blue}{4x-1}\right) \cdot \left( 2x+3\right) = 8x^2+12x-2x-3 $$ |
| ② | Combine like terms: $$ 8x^2+ \color{blue}{12x} \color{blue}{-2x} -3 = 8x^2+ \color{blue}{10x} -3 $$ |
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