Question
Answer
$$(4x^3-5x^2-3x+7)(2x-5)=8x^4-30x^3+19x^2+29x-35$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x^3-5x^2-3x+7)(2x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}8x^4-30x^3+19x^2+29x-35\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x^3-5x^2-3x+7}\right) $ by each term in $ \left( 2x-5\right) $. $$ \left( \color{blue}{4x^3-5x^2-3x+7}\right) \cdot \left( 2x-5\right) = 8x^4-20x^3-10x^3+25x^2-6x^2+15x+14x-35 $$ |
| ② | Combine like terms: $$ 8x^4 \color{blue}{-20x^3} \color{blue}{-10x^3} + \color{red}{25x^2} \color{red}{-6x^2} + \color{green}{15x} + \color{green}{14x} -35 = \\ = 8x^4 \color{blue}{-30x^3} + \color{red}{19x^2} + \color{green}{29x} -35 $$ |
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