Question
Answer
$$4x^3-3x^2-7-(2x^3+x^2-4x)=2x^3-4x^2+4x-7$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4x^3-3x^2-7-(2x^3+x^2-4x)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^3-3x^2-7-2x^3-x^2+4x \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2x^3-4x^2+4x-7\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2x^3+x^2-4x \right) = -2x^3-x^2+4x $$ |
| ② | Combine like terms: $$ \color{blue}{4x^3} \color{red}{-3x^2} -7 \color{blue}{-2x^3} \color{red}{-x^2} +4x = \color{blue}{2x^3} \color{red}{-4x^2} +4x-7 $$ |
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