Question
Answer
$$(4x^2-10x-24)(x-4)=4x^3-26x^2+16x+96$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4x^2-10x-24)(x-4)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4x^3-16x^2-10x^2+40x-24x+96 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4x^3-26x^2+16x+96\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4x^2-10x-24}\right) $ by each term in $ \left( x-4\right) $. $$ \left( \color{blue}{4x^2-10x-24}\right) \cdot \left( x-4\right) = 4x^3-16x^2-10x^2+40x-24x+96 $$ |
| ② | Combine like terms: $$ 4x^3 \color{blue}{-16x^2} \color{blue}{-10x^2} + \color{red}{40x} \color{red}{-24x} +96 = 4x^3 \color{blue}{-26x^2} + \color{red}{16x} +96 $$ |
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