Question
Answer
$$4t^2-3t+5-7t^2+t+6=-3t^2-2t+11$$
Explanation
| $$ \begin{aligned}4t^2-3t+5-7t^2+t+6& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-3t^2-2t+11\end{aligned} $$ | |
| ① | Combine like terms: $$ \color{blue}{4t^2} \color{red}{-3t} + \color{green}{5} \color{blue}{-7t^2} + \color{red}{t} + \color{green}{6} = \color{blue}{-3t^2} \color{red}{-2t} + \color{green}{11} $$ |
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