Question
Answer
$$(4r-6)(3r+2)=12r^2-10r-12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4r-6)(3r+2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12r^2+8r-18r-12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12r^2-10r-12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4r-6}\right) $ by each term in $ \left( 3r+2\right) $. $$ \left( \color{blue}{4r-6}\right) \cdot \left( 3r+2\right) = 12r^2+8r-18r-12 $$ |
| ② | Combine like terms: $$ 12r^2+ \color{blue}{8r} \color{blue}{-18r} -12 = 12r^2 \color{blue}{-10r} -12 $$ |
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