Question
Answer
$$(4q-10)(5q^2+6q-5)=20q^3-26q^2-80q+50$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4q-10)(5q^2+6q-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}20q^3+24q^2-20q-50q^2-60q+50 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}20q^3-26q^2-80q+50\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4q-10}\right) $ by each term in $ \left( 5q^2+6q-5\right) $. $$ \left( \color{blue}{4q-10}\right) \cdot \left( 5q^2+6q-5\right) = 20q^3+24q^2-20q-50q^2-60q+50 $$ |
| ② | Combine like terms: $$ 20q^3+ \color{blue}{24q^2} \color{red}{-20q} \color{blue}{-50q^2} \color{red}{-60q} +50 = 20q^3 \color{blue}{-26q^2} \color{red}{-80q} +50 $$ |
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