Question
Answer
$$(4+7a^2)^2=49a^4+56a^2+16$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4+7a^2)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16+56a^2+49a^4 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}49a^4+56a^2+16\end{aligned} $$ | |
| ① | Find $ \left(4+7a^2\right)^2 $ using formula. $$ (A + B)^2 = \color{blue}{A^2} + 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 4 } $ and $ B = \color{red}{ 7a^2 }$. $$ \begin{aligned}\left(4+7a^2\right)^2 = \color{blue}{4^2} +2 \cdot 4 \cdot 7a^2 + \color{red}{\left( 7a^2 \right)^2} = 16+56a^2+49a^4\end{aligned} $$ |
| ② | Combine like terms: $$ 49a^4+56a^2+16 = 49a^4+56a^2+16 $$ |
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