Question
Answer
$$(4p-3)^2=16p^2-24p+9$$
Explanation
| $$ \begin{aligned}(4p-3)^2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}16p^2-24p+9\end{aligned} $$ | |
| ① | Find $ \left(4p-3\right)^2 $ using formula. $$ (A - B)^2 = \color{blue}{A^2} - 2 \cdot A \cdot B + \color{red}{B^2} $$where $ A = \color{blue}{ 4p } $ and $ B = \color{red}{ 3 }$. $$ \begin{aligned}\left(4p-3\right)^2 = \color{blue}{\left( 4p \right)^2} -2 \cdot 4p \cdot 3 + \color{red}{3^2} = 16p^2-24p+9\end{aligned} $$ |
This page was created using
Simplify polynomials calculator