Question
Answer
$$4n^4-8n+4-(8n^2+4n^4+1)=-8n^2-8n+3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}4n^4-8n+4-(8n^2+4n^4+1)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4n^4-8n+4-8n^2-4n^4-1 \xlongequal{ } \\[1 em] & \xlongequal{ } \cancel{4n^4}-8n+4-8n^2 -\cancel{4n^4}-1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-8n^2-8n+3\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 8n^2+4n^4+1 \right) = -8n^2-4n^4-1 $$ |
| ② | Combine like terms: $$ \, \color{blue}{ \cancel{4n^4}} \,-8n+ \color{green}{4} -8n^2 \, \color{blue}{ -\cancel{4n^4}} \, \color{green}{-1} = -8n^2-8n+ \color{green}{3} $$ |
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