Question
Answer
$$(4a+1)(6a-3)=24a^2-6a-3$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4a+1)(6a-3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}24a^2-12a+6a-3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}24a^2-6a-3\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4a+1}\right) $ by each term in $ \left( 6a-3\right) $. $$ \left( \color{blue}{4a+1}\right) \cdot \left( 6a-3\right) = 24a^2-12a+6a-3 $$ |
| ② | Combine like terms: $$ 24a^2 \color{blue}{-12a} + \color{blue}{6a} -3 = 24a^2 \color{blue}{-6a} -3 $$ |
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