Question
Answer
$$(4a^2+9a+15)(ab+3)=4a^3b+9a^2b+12a^2+15ab+27a+45$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4a^2+9a+15)(ab+3)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4a^3b+12a^2+9a^2b+27a+15ab+45 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}4a^3b+9a^2b+12a^2+15ab+27a+45\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4a^2+9a+15}\right) $ by each term in $ \left( ab+3\right) $. $$ \left( \color{blue}{4a^2+9a+15}\right) \cdot \left( ab+3\right) = 4a^3b+12a^2+9a^2b+27a+15ab+45 $$ |
| ② | Combine like terms: $$ 4a^3b+9a^2b+12a^2+15ab+27a+45 = 4a^3b+9a^2b+12a^2+15ab+27a+45 $$ |
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