Question
Answer
$$\dfrac{49w^2-1}{7w^2+13w-2}=\dfrac{7w+1}{w+2}$$
Explanation
| $$ \begin{aligned}\frac{49w^2-1}{7w^2+13w-2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7w+1}{w+2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{49w^2-1}{7w^2+13w-2} $ to $ \dfrac{7w+1}{w+2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{7w-1}$. $$ \begin{aligned} \frac{49w^2-1}{7w^2+13w-2} & =\frac{ \left( 7w+1 \right) \cdot \color{blue}{ \left( 7w-1 \right) }}{ \left( w+2 \right) \cdot \color{blue}{ \left( 7w-1 \right) }} = \\[1ex] &= \frac{7w+1}{w+2} \end{aligned} $$ |
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