Question
Answer
$$(4-x)(8-6x+x^2)=-x^3+10x^2-32x+32$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(4-x)(8-6x+x^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}32-24x+4x^2-8x+6x^2-x^3 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-x^3+10x^2-32x+32\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{4-x}\right) $ by each term in $ \left( 8-6x+x^2\right) $. $$ \left( \color{blue}{4-x}\right) \cdot \left( 8-6x+x^2\right) = 32-24x+4x^2-8x+6x^2-x^3 $$ |
| ② | Combine like terms: $$ 32 \color{blue}{-24x} + \color{red}{4x^2} \color{blue}{-8x} + \color{red}{6x^2} -x^3 = -x^3+ \color{red}{10x^2} \color{blue}{-32x} +32 $$ |
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