Question
Answer
$$3y\cdot2-4y+1-y\cdot2+y-2=y-1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3y\cdot2-4y+1-y\cdot2+y-2& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6y-4y+1-y-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}2y+1-y-2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}y-1\end{aligned} $$ | |
| ① | $$ 3 y \cdot 2 = 6 y $$ Combine like terms: $$ \color{blue}{-2y} + \color{blue}{y} -2 = \color{blue}{-y} -2 $$ |
| ② | Combine like terms: $$ \color{blue}{6y} \color{blue}{-4y} +1 = \color{blue}{2y} +1 $$ |
| ③ | Combine like terms: $$ \color{blue}{2y} + \color{red}{1} \color{blue}{-y} \color{red}{-2} = \color{blue}{y} \color{red}{-1} $$ |
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