Question
Answer
$$(3x-7)(2x-5)=6x^2-29x+35$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-7)(2x-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^2-15x-14x+35 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}6x^2-29x+35\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-7}\right) $ by each term in $ \left( 2x-5\right) $. $$ \left( \color{blue}{3x-7}\right) \cdot \left( 2x-5\right) = 6x^2-15x-14x+35 $$ |
| ② | Combine like terms: $$ 6x^2 \color{blue}{-15x} \color{blue}{-14x} +35 = 6x^2 \color{blue}{-29x} +35 $$ |
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