Question
Answer
$$(3x-2y)^3=27x^3-54x^2y+36xy^2-8y^3$$
Explanation
| $$ \begin{aligned}(3x-2y)^3& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}27x^3-54x^2y+36xy^2-8y^3\end{aligned} $$ | |
| ① | Find $ \left(3x-2y\right)^3 $ using formula $$ (A - B) = A^3 - 3A^2B + 3AB^2 - B^3 $$where $ A = 3x $ and $ B = 2y $. $$ \left(3x-2y\right)^3 = \left( 3x \right)^3-3 \cdot \left( 3x \right)^2 \cdot 2y + 3 \cdot 3x \cdot \left( 2y \right)^2-\left( 2y \right)^3 = 27x^3-54x^2y+36xy^2-8y^3 $$ |
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