Question
Answer
$$(3x-2y)(4x-3y+5)=12x^2-17xy+6y^2+15x-10y$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-2y)(4x-3y+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^2-9xy+15x-8xy+6y^2-10y \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^2-17xy+6y^2+15x-10y\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-2y}\right) $ by each term in $ \left( 4x-3y+5\right) $. $$ \left( \color{blue}{3x-2y}\right) \cdot \left( 4x-3y+5\right) = 12x^2-9xy+15x-8xy+6y^2-10y $$ |
| ② | Combine like terms: $$ 12x^2 \color{blue}{-9xy} +15x \color{blue}{-8xy} +6y^2-10y = 12x^2 \color{blue}{-17xy} +6y^2+15x-10y $$ |
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