Question
Answer
$$(3x-2)(x^2+bx-5)=3bx^2+3x^3-2bx-2x^2-15x+10$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-2)(x^2+bx-5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^3+3bx^2-15x-2x^2-2bx+10 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}3bx^2+3x^3-2bx-2x^2-15x+10\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-2}\right) $ by each term in $ \left( x^2+bx-5\right) $. $$ \left( \color{blue}{3x-2}\right) \cdot \left( x^2+bx-5\right) = 3x^3+3bx^2-15x-2x^2-2bx+10 $$ |
| ② | Combine like terms: $$ 3bx^2+3x^3-2bx-2x^2-15x+10 = 3bx^2+3x^3-2bx-2x^2-15x+10 $$ |
This page was created using
Simplify polynomials calculator