Question
Answer
$$(3x-2)(4x^2+4x-6)=12x^3+4x^2-26x+12$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}(3x-2)(4x^2+4x-6)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}12x^3+12x^2-18x-8x^2-8x+12 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}12x^3+4x^2-26x+12\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x-2}\right) $ by each term in $ \left( 4x^2+4x-6\right) $. $$ \left( \color{blue}{3x-2}\right) \cdot \left( 4x^2+4x-6\right) = 12x^3+12x^2-18x-8x^2-8x+12 $$ |
| ② | Combine like terms: $$ 12x^3+ \color{blue}{12x^2} \color{red}{-18x} \color{blue}{-8x^2} \color{red}{-8x} +12 = 12x^3+ \color{blue}{4x^2} \color{red}{-26x} +12 $$ |
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