Question
Answer
$$(3x^2+5)(2x-9)=6x^3-27x^2+10x-45$$
Explanation
| $$ \begin{aligned}(3x^2+5)(2x-9)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6x^3-27x^2+10x-45\end{aligned} $$ | |
| ① | Multiply each term of $ \left( \color{blue}{3x^2+5}\right) $ by each term in $ \left( 2x-9\right) $. $$ \left( \color{blue}{3x^2+5}\right) \cdot \left( 2x-9\right) = 6x^3-27x^2+10x-45 $$ |
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