Question
Answer
$$3x^2+2x^2y-(2x^2y+5y^2+6x^2)=-3x^2-5y^2$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}3x^2+2x^2y-(2x^2y+5y^2+6x^2)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x^2+2x^2y-2x^2y-5y^2-6x^2 \xlongequal{ } \\[1 em] & \xlongequal{ }3x^2+ \cancel{2x^2y} -\cancel{2x^2y}-5y^2-6x^2 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-3x^2-5y^2\end{aligned} $$ | |
| ① | Remove the parentheses by changing the sign of each term within them. $$ - \left( 2x^2y+5y^2+6x^2 \right) = -2x^2y-5y^2-6x^2 $$ |
| ② | Combine like terms: $$ \color{blue}{3x^2} + \, \color{red}{ \cancel{2x^2y}} \, \, \color{red}{ -\cancel{2x^2y}} \,-5y^2 \color{blue}{-6x^2} = \color{blue}{-3x^2} -5y^2 $$ |
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