| $$ \begin{aligned}\frac{3x^2-16x-12}{x-6}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3x+2\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3x^2-16x-12}{x-6} $ to $ 3x+2$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-6}$. $$ \begin{aligned} \frac{3x^2-16x-12}{x-6} & =\frac{ \left( 3x+2 \right) \cdot \color{blue}{ \left( x-6 \right) }}{ 1 \cdot \color{blue}{ \left( x-6 \right) }} = \\[1ex] &= \frac{3x+2}{1} =3x+2 \end{aligned} $$ |