Question
Answer
$$3x^2\cdot2x^3 \cdot \dfrac{7y^7}{14y^{14}}=\dfrac{42x^5y^7}{14y^{14}}$$
Explanation
| $$ \begin{aligned}3x^2\cdot2x^3\frac{7y^7}{14y^{14}}& \xlongequal{ }6x^5\frac{7y^7}{14y^{14}} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{42x^5y^7}{14y^{14}}\end{aligned} $$ | |
| ① | Multiply $6x^5$ by $ \dfrac{7y^7}{14y^{14}} $ to get $ \dfrac{ 42x^5y^7 }{ 14y^{14} } $. Step 1: Write $ 6x^5 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 6x^5 \cdot \frac{7y^7}{14y^{14}} & \xlongequal{\text{Step 1}} \frac{6x^5}{\color{red}{1}} \cdot \frac{7y^7}{14y^{14}} \xlongequal{\text{Step 2}} \frac{ 6x^5 \cdot 7y^7 }{ 1 \cdot 14y^{14} } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 42x^5y^7 }{ 14y^{14} } \end{aligned} $$ |
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